Given an array of integers nums
, sort the array in increasing order based on the frequency of the values. If multiple values have the same frequency, sort them in decreasing order.
Return the sorted array.
Input: nums = [1,1,2,2,2,3] Output: [3,1,1,2,2,2] Explanation: '3' has a frequency of 1, '1' has a frequency of 2, and '2' has a frequency of 3.
Input: nums = [2,3,1,3,2] Output: [1,3,3,2,2] Explanation: '2' and '3' both have a frequency of 2, so they are sorted in decreasing order.
Input: nums = [-1,1,-6,4,5,-6,1,4,1] Output: [5,-1,4,4,-6,-6,1,1,1]
1 <= nums.length <= 100
-100 <= nums[i] <= 100
use std::collections::HashMap;implSolution{pubfnfrequency_sort(mutnums:Vec<i32>) -> Vec<i32>{letmut count = HashMap::new();for&num in&nums {*count.entry(num).or_insert(0) += 1;} nums.sort_unstable_by(|a, b| b.cmp(a)); nums.sort_by_key(|k| count.get(k).unwrap()); nums }}